--- trunk/dyn3d/coefpoly.f	2013/11/15 18:45:49	76
+++ trunk/dyn3d/coefpoly.f90	2014/03/05 14:38:41	81
@@ -1,40 +1,39 @@
-!
-! $Header: /home/cvsroot/LMDZ4/libf/dyn3d/coefpoly.F,v 1.1.1.1 2004/05/19 12:53:05 lmdzadmin Exp $
-!
-      SUBROUTINE coefpoly ( Xf1, Xf2, Xprim1, Xprim2, xtild1,xtild2 ,
-     ,                                          a0,a1,a2,a3         )
-      IMPLICIT NONE
-c
-c   ...  Auteur :   P. Le Van  ...
-c
-c
-c    Calcul des coefficients a0, a1, a2, a3 du polynome de degre 3 qui
-c      satisfait aux 4 equations  suivantes :
-
-c    a0 + a1*xtild1 + a2*xtild1*xtild1 + a3*xtild1*xtild1*xtild1 = Xf1
-c    a0 + a1*xtild2 + a2*xtild2*xtild2 + a3*xtild2*xtild2*xtild2 = Xf2
-c               a1  +     2.*a2*xtild1 +     3.*a3*xtild1*xtild1 = Xprim1
-c               a1  +     2.*a2*xtild2 +     3.*a3*xtild2*xtild2 = Xprim2
-
-c  On en revient a resoudre un systeme de 4 equat.a 4 inconnues a0,a1,a2,a3
-
-      DOUBLE PRECISION Xf1, Xf2,Xprim1,Xprim2, xtild1,xtild2, xi 
-      DOUBLE PRECISION Xfout, Xprim
-      DOUBLE PRECISION a1,a2,a3,a0, xtil1car, xtil2car,derr,x1x2car
-
-      xtil1car = xtild1 * xtild1
-      xtil2car = xtild2 * xtild2 
-
-      derr= 2. *(Xf2-Xf1)/( xtild1-xtild2)
-
-      x1x2car = ( xtild1-xtild2)*(xtild1-xtild2)
-
-      a3 = (derr + Xprim1+Xprim2 )/x1x2car
-      a2     = ( Xprim1 - Xprim2 + 3.* a3 * ( xtil2car-xtil1car ) )    /
-     /           (  2.* ( xtild1 - xtild2 )  )
 
-      a1     = Xprim1 -3.* a3 * xtil1car     -2.* a2 * xtild1
-      a0     =  Xf1 - a3 * xtild1* xtil1car -a2 * xtil1car - a1 *xtild1
+! $Header: /home/cvsroot/LMDZ4/libf/dyn3d/coefpoly.F,v 1.1.1.1 2004/05/19
+! 12:53:05 lmdzadmin Exp $
 
-      RETURN
-      END
+SUBROUTINE coefpoly(xf1, xf2, xprim1, xprim2, xtild1, xtild2, a0, a1, a2, a3)
+  IMPLICIT NONE
+
+  ! ...  Auteur :   P. Le Van  ...
+
+
+  ! Calcul des coefficients a0, a1, a2, a3 du polynome de degre 3 qui
+  ! satisfait aux 4 equations  suivantes :
+
+  ! a0 + a1*xtild1 + a2*xtild1*xtild1 + a3*xtild1*xtild1*xtild1 = Xf1
+  ! a0 + a1*xtild2 + a2*xtild2*xtild2 + a3*xtild2*xtild2*xtild2 = Xf2
+  ! a1  +     2.*a2*xtild1 +     3.*a3*xtild1*xtild1 = Xprim1
+  ! a1  +     2.*a2*xtild2 +     3.*a3*xtild2*xtild2 = Xprim2
+
+  ! On en revient a resoudre un systeme de 4 equat.a 4 inconnues a0,a1,a2,a3
+
+  DOUBLE PRECISION xf1, xf2, xprim1, xprim2, xtild1, xtild2, xi
+  DOUBLE PRECISION xfout, xprim
+  DOUBLE PRECISION a1, a2, a3, a0, xtil1car, xtil2car, derr, x1x2car
+
+  xtil1car = xtild1*xtild1
+  xtil2car = xtild2*xtild2
+
+  derr = 2.*(xf2-xf1)/(xtild1-xtild2)
+
+  x1x2car = (xtild1-xtild2)*(xtild1-xtild2)
+
+  a3 = (derr+xprim1+xprim2)/x1x2car
+  a2 = (xprim1-xprim2+3.*a3*(xtil2car-xtil1car))/(2.*(xtild1-xtild2))
+
+  a1 = xprim1 - 3.*a3*xtil1car - 2.*a2*xtild1
+  a0 = xf1 - a3*xtild1*xtil1car - a2*xtil1car - a1*xtild1
+
+  RETURN
+END SUBROUTINE coefpoly