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guez |
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SUBROUTINE cv3_feed(len,nd,t,q,qs,p,ph,hm,gz & |
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,nk,icb,icbmax,iflag,tnk,qnk,gznk,plcl) |
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use cvparam3 |
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implicit none |
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!================================================================ |
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! Purpose: CONVECTIVE FEED |
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! |
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! Main differences with cv_feed: |
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! - ph added in input |
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! - here, nk(i)=minorig |
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! - icb defined differently (plcl compared with ph instead of p) |
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! |
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! Main differences with convect3: |
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! - we do not compute dplcldt and dplcldr of CLIFT anymore |
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! - values iflag different (but tests identical) |
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! - A,B explicitely defined (!...) |
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!================================================================ |
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! inputs: |
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integer len, nd |
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real t(len,nd), q(len,nd), qs(len,nd), p(len,nd) |
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real hm(len,nd), gz(len,nd) |
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real ph(len,nd+1) |
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! outputs: |
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integer iflag(len), nk(len), icb(len), icbmax |
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real tnk(len), qnk(len), gznk(len), plcl(len) |
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! local variables: |
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integer i, k |
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integer ihmin(len) |
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real work(len) |
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real pnk(len), qsnk(len), rh(len), chi(len) |
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real A, B ! convect3 |
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!ym |
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plcl=0.0 |
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!@ !------------------------------------------------------------------- |
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!@ ! --- Find level of minimum moist static energy |
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!@ ! --- If level of minimum moist static energy coincides with |
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!@ ! --- or is lower than minimum allowable parcel origin level, |
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!@ ! --- set iflag to 6. |
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!@ !------------------------------------------------------------------- |
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!@ |
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!@ do 180 i=1,len |
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!@ work(i)=1.0e12 |
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!@ ihmin(i)=nl |
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!@ 180 continue |
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!@ do 200 k=2,nlp |
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!@ do 190 i=1,len |
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!@ if((hm(i,k).lt.work(i)).and. |
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!@ & (hm(i,k).lt.hm(i,k-1)))then |
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!@ work(i)=hm(i,k) |
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!@ ihmin(i)=k |
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!@ endif |
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!@ 190 continue |
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!@ 200 continue |
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!@ do 210 i=1,len |
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!@ ihmin(i)=min(ihmin(i),nlm) |
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!@ if(ihmin(i).le.minorig)then |
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!@ iflag(i)=6 |
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!@ endif |
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!@ 210 continue |
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!@ c |
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!@ !------------------------------------------------------------------- |
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!@ ! --- Find that model level below the level of minimum moist static |
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!@ ! --- energy that has the maximum value of moist static energy |
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!@ !------------------------------------------------------------------- |
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!@ |
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!@ do 220 i=1,len |
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!@ work(i)=hm(i,minorig) |
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!@ nk(i)=minorig |
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!@ 220 continue |
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!@ do 240 k=minorig+1,nl |
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!@ do 230 i=1,len |
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!@ if((hm(i,k).gt.work(i)).and.(k.le.ihmin(i)))then |
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!@ work(i)=hm(i,k) |
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!@ nk(i)=k |
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!@ endif |
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!@ 230 continue |
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!@ 240 continue |
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!------------------------------------------------------------------- |
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! --- Origin level of ascending parcels for convect3: |
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!------------------------------------------------------------------- |
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do 220 i=1,len |
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nk(i)=minorig |
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220 continue |
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!------------------------------------------------------------------- |
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! --- Check whether parcel level temperature and specific humidity |
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! --- are reasonable |
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!------------------------------------------------------------------- |
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do 250 i=1,len |
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if( ( ( t(i,nk(i)).lt.250.0 ) & |
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.or.( q(i,nk(i)).le.0.0 ) ) & |
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.and. & |
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( iflag(i).eq.0) ) iflag(i)=7 |
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250 continue |
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!------------------------------------------------------------------- |
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! --- Calculate lifted condensation level of air at parcel origin level |
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! --- (Within 0.2% of formula of Bolton, MON. WEA. REV.,1980) |
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!------------------------------------------------------------------- |
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A = 1669.0 ! convect3 |
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B = 122.0 ! convect3 |
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do 260 i=1,len |
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if (iflag(i).ne.7) then ! modif sb Jun7th 2002 |
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tnk(i)=t(i,nk(i)) |
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qnk(i)=q(i,nk(i)) |
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gznk(i)=gz(i,nk(i)) |
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pnk(i)=p(i,nk(i)) |
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qsnk(i)=qs(i,nk(i)) |
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! |
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rh(i)=qnk(i)/qsnk(i) |
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! ori rh(i)=min(1.0,rh(i)) ! removed for convect3 |
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! ori chi(i)=tnk(i)/(1669.0-122.0*rh(i)-tnk(i)) |
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chi(i)=tnk(i)/(A-B*rh(i)-tnk(i)) ! convect3 |
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plcl(i)=pnk(i)*(rh(i)**chi(i)) |
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if(((plcl(i).lt.200.0).or.(plcl(i).ge.2000.0)) & |
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.and.(iflag(i).eq.0))iflag(i)=8 |
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endif ! iflag=7 |
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260 continue |
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!------------------------------------------------------------------- |
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! --- Calculate first level above lcl (=icb) |
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!------------------------------------------------------------------- |
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!@ do 270 i=1,len |
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!@ icb(i)=nlm |
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!@ 270 continue |
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!@c |
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!@ do 290 k=minorig,nl |
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!@ do 280 i=1,len |
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!@ if((k.ge.(nk(i)+1)).and.(p(i,k).lt.plcl(i))) |
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!@ & icb(i)=min(icb(i),k) |
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!@ 280 continue |
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!@ 290 continue |
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!@c |
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!@ do 300 i=1,len |
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!@ if((icb(i).ge.nlm).and.(iflag(i).eq.0))iflag(i)=9 |
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!@ 300 continue |
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do 270 i=1,len |
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icb(i)=nlm |
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270 continue |
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! |
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! la modification consiste a comparer plcl a ph et non a p: |
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! icb est defini par : ph(icb)<plcl<ph(icb-1) |
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!@ do 290 k=minorig,nl |
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do 290 k=3,nl-1 ! modif pour que icb soit sup/egal a 2 |
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do 280 i=1,len |
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if( ph(i,k).lt.plcl(i) ) icb(i)=min(icb(i),k) |
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280 continue |
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290 continue |
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! |
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do 300 i=1,len |
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!@ if((icb(i).ge.nlm).and.(iflag(i).eq.0))iflag(i)=9 |
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if((icb(i).eq.nlm).and.(iflag(i).eq.0))iflag(i)=9 |
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300 continue |
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do 400 i=1,len |
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icb(i) = icb(i)-1 ! icb sup ou egal a 2 |
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400 continue |
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! |
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! Compute icbmax. |
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! |
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icbmax=2 |
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do 310 i=1,len |
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!! icbmax=max(icbmax,icb(i)) |
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if (iflag(i).lt.7) icbmax=max(icbmax,icb(i)) ! sb Jun7th02 |
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310 continue |
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return |
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end |
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