Changeset 11353 for NEMO/branches/2019/dev_r10984_HPC-13_IRRMANN_BDY_optimization/doc/latex/NEMO/subfiles/annex_B.tex
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NEMO/branches/2019/dev_r10984_HPC-13_IRRMANN_BDY_optimization/doc/latex/NEMO/subfiles/annex_B.tex
r11263 r11353 53 53 { 54 54 \begin{array}{*{20}l} 55 D^T=& \frac{1}{e_1\,e_2\,e_3 }\;\left[ {\ \ \ \ e_2\,e_3\,A^{lT} \;\left. 56 {\frac{\partial }{\partial i}\left( {\frac{1}{e_1}\;\left. {\frac{\partial T}{\partial i}} \right|_s -\frac{\sigma_1 }{e_3 }\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right. \\ 57 &\qquad \quad \ \ \ +e_1\,e_3\,A^{lT} \;\left. {\frac{\partial }{\partial j}\left( {\frac{1}{e_2 }\;\left. {\frac{\partial T}{\partial j}} \right|_s -\frac{\sigma_2 }{e_3 }\;\frac{\partial T}{\partial s}} \right)} \right|_s \\ 58 &\qquad \quad \ \ \ + e_1\,e_2\,A^{lT} \;\frac{\partial }{\partial s}\left( {-\frac{\sigma_1 }{e_1 }\;\left. {\frac{\partial T}{\partial i}} \right|_s -\frac{\sigma_2 }{e_2 }\;\left. {\frac{\partial T}{\partial j}} \right|_s } \right. 59 \left. {\left. {+\left( {\varepsilon +\sigma_1^2+\sigma_2 ^2} \right)\;\frac{1}{e_3 }\;\frac{\partial T}{\partial s}} \right)\;\;} \right] 55 D^T= \frac{1}{e_1\,e_2\,e_3 } & \left\{ \quad \quad \frac{\partial }{\partial i} \left. \left[ e_2\,e_3 \, A^{lT} 56 \left( \ \frac{1}{e_1}\; \left. \frac{\partial T}{\partial i} \right|_s 57 -\frac{\sigma_1 }{e_3 } \; \frac{\partial T}{\partial s} \right) \right] \right|_s \right. \\ 58 & \quad \ + \ \left. \frac{\partial }{\partial j} \left. \left[ e_1\,e_3 \, A^{lT} 59 \left( \ \frac{1}{e_2 }\; \left. \frac{\partial T}{\partial j} \right|_s 60 -\frac{\sigma_2 }{e_3 } \; \frac{\partial T}{\partial s} \right) \right] \right|_s \right. \\ 61 & \quad \ + \ \left. e_1\,e_2\, \frac{\partial }{\partial s} \left[ A^{lT} \; \left( 62 -\frac{\sigma_1 }{e_1 } \; \left. \frac{\partial T}{\partial i} \right|_s 63 -\frac{\sigma_2 }{e_2 } \; \left. \frac{\partial T}{\partial j} \right|_s 64 +\left( \varepsilon +\sigma_1^2+\sigma_2 ^2 \right) \; \frac{1}{e_3 } \; \frac{\partial T}{\partial s} \right) \; \right] \; \right\} . 60 65 \end{array} 61 66 } 62 67 \end{align*} 63 68 64 Equation\autoref{apdx:B2} is obtained from \autoref{apdx:B1} without any additional assumption.69 \autoref{apdx:B2} is obtained from \autoref{apdx:B1} without any additional assumption. 65 70 Indeed, for the special case $k=z$ and thus $e_3 =1$, 66 71 we introduce an arbitrary vertical coordinate $s = s (i,j,z)$ as in \autoref{apdx:A} and … … 90 95 { 91 96 \begin{array}{*{20}l} 92 \intertext{Noting that $\frac{1}{e_1} \left. \frac{\partial e_3 }{\partial i} \right|_s = \frac{\partial \sigma_1 }{\partial s}$, itbecomes:}97 \intertext{Noting that $\frac{1}{e_1} \left. \frac{\partial e_3 }{\partial i} \right|_s = \frac{\partial \sigma_1 }{\partial s}$, this becomes:} 93 98 % 94 & =\frac{1}{e_1\,e_2\,e_3 }\left[ {\left. {\;\;\;\frac{\partial }{\partial i}\left( {\frac{e_2\,e_3 }{e_1}\,A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s } \right)} \right|_s \left. -\, {e_3 \frac{\partial }{\partial i}\left( {\frac{e_2 \,\sigma_1 }{e_3 }A^{lT}\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right. \\99 D^T & =\frac{1}{e_1\,e_2\,e_3 }\left[ {\left. {\;\;\;\frac{\partial }{\partial i}\left( {\frac{e_2\,e_3 }{e_1}\,A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s } \right)} \right|_s \left. -\, {e_3 \frac{\partial }{\partial i}\left( {\frac{e_2 \,\sigma_1 }{e_3 }A^{lT}\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right. \\ 95 100 & \qquad \qquad \quad -e_2 A^{lT}\;\frac{\partial \sigma_1 }{\partial s}\left. {\frac{\partial T}{\partial i}} \right|_s -e_1 \,\sigma_1 \frac{\partial }{\partial s}\left( {\frac{e_2 }{e_1 }A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s } \right) \\ 96 & \qquad \qquad \quad\shoveright{ \left. { +e_1 \,\sigma_1 \frac{\partial }{\partial s}\left( {\frac{e_2 \,\sigma_1 }{e_3 }A^{lT}\;\frac{\partial T}{\partial s}} \right)+\frac{\partial }{\partial s}\left( {\frac{e_1 \,e_2 }{e_3 }A^{vT}\;\frac{\partial T}{\partial z}} \right)\;\;\;} \right] }\\101 & \qquad \qquad \quad\shoveright{ \left. { +e_1 \,\sigma_1 \frac{\partial }{\partial s}\left( {\frac{e_2 \,\sigma_1 }{e_3 }A^{lT}\;\frac{\partial T}{\partial s}} \right)+\frac{\partial }{\partial s}\left( {\frac{e_1 \,e_2 }{e_3 }A^{vT}\;\frac{\partial T}{\partial s}} \right)\;\;\;} \right] }\\ 97 102 \\ 98 103 &=\frac{1}{e_1 \,e_2 \,e_3 } \left[ {\left. {\;\;\;\frac{\partial }{\partial i} \left( {\frac{e_2 \,e_3 }{e_1 }A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s } \right)} \right|_s \left. {-\frac{\partial }{\partial i}\left( {e_2 \,\sigma_1 A^{lT}\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right. \\ 99 104 & \qquad \qquad \quad \left. {+\frac{e_2 \,\sigma_1 }{e_3}A^{lT}\;\frac{\partial T}{\partial s} \;\frac{\partial e_3 }{\partial i}} \right|_s -e_2 A^{lT}\;\frac{\partial \sigma_1 }{\partial s}\left. {\frac{\partial T}{\partial i}} \right|_s \\ 100 105 & \qquad \qquad \quad-e_2 \,\sigma_1 \frac{\partial}{\partial s}\left( {A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s } \right)+\frac{\partial }{\partial s}\left( {\frac{e_1 \,e_2 \,\sigma_1 ^2}{e_3 }A^{lT}\;\frac{\partial T}{\partial s}} \right) \\ 101 & \qquad \qquad \quad\shoveright{ \left. {-\frac{\partial \left( {e_1 \,e_2 \,\sigma_1 } \right)}{\partial s} \left( {\frac{\sigma_1 }{e_3}A^{lT}\;\frac{\partial T}{\partial s}} \right) + \frac{\partial }{\partial s}\left( {\frac{e_1 \,e_2 }{e_3 }A^{vT}\;\frac{\partial T}{\partial s}} \right)\;\;\;} \right]} 106 & \qquad \qquad \quad\shoveright{ \left. {-\frac{\partial \left( {e_1 \,e_2 \,\sigma_1 } \right)}{\partial s} \left( {\frac{\sigma_1 }{e_3}A^{lT}\;\frac{\partial T}{\partial s}} \right) + \frac{\partial }{\partial s}\left( {\frac{e_1 \,e_2 }{e_3 }A^{vT}\;\frac{\partial T}{\partial s}} \right)\;\;\;} \right]} . 102 107 \end{array} 103 108 } \\ … … 105 110 \begin{array}{*{20}l} 106 111 % 107 \intertext{ using the same remark as just above, itbecomes:}112 \intertext{Using the same remark as just above, $D^T$ becomes:} 108 113 % 109 &= \frac{1}{e_1 \,e_2 \,e_3 } \left[ {\left. {\;\;\;\frac{\partial }{\partial i} \left( {\frac{e_2 \,e_3 }{e_1 }A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s -e_2 \,\sigma_1 A^{lT}\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right.\;\;\; \\114 D^T &= \frac{1}{e_1 \,e_2 \,e_3 } \left[ {\left. {\;\;\;\frac{\partial }{\partial i} \left( {\frac{e_2 \,e_3 }{e_1 }A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s -e_2 \,\sigma_1 A^{lT}\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right.\;\;\; \\ 110 115 & \qquad \qquad \quad+\frac{e_1 \,e_2 \,\sigma_1 }{e_3 }A^{lT}\;\frac{\partial T}{\partial s}\;\frac{\partial \sigma_1 }{\partial s} - \frac {\sigma_1 }{e_3} A^{lT} \;\frac{\partial \left( {e_1 \,e_2 \,\sigma_1 } \right)}{\partial s}\;\frac{\partial T}{\partial s} \\ 111 116 & \qquad \qquad \quad-e_2 \left( {A^{lT}\;\frac{\partial \sigma_1 }{\partial s}\left. {\frac{\partial T}{\partial i}} \right|_s +\frac{\partial }{\partial s}\left( {\sigma_1 A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s } \right)-\frac{\partial \sigma_1 }{\partial s}\;A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s } \right) \\ 112 & \qquad \qquad \quad\shoveright{\left. {+\frac{\partial }{\partial s}\left( {\frac{e_1 \,e_2 \,\sigma_1 ^2}{e_3 }A^{lT}\;\frac{\partial T}{\partial s}+\frac{e_1 \,e_2}{e_3 }A^{vT}\;\frac{\partial T}{\partial s}} \right)\;\;\;} \right] }117 & \qquad \qquad \quad\shoveright{\left. {+\frac{\partial }{\partial s}\left( {\frac{e_1 \,e_2 \,\sigma_1 ^2}{e_3 }A^{lT}\;\frac{\partial T}{\partial s}+\frac{e_1 \,e_2}{e_3 }A^{vT}\;\frac{\partial T}{\partial s}} \right)\;\;\;} \right] . } 113 118 \end{array} 114 119 } \\ … … 117 122 % 118 123 \intertext{Since the horizontal scale factors do not depend on the vertical coordinate, 119 the last term of the first line and the first term of the lastline cancel, while120 the second line reduces to a single vertical derivative, so it becomes:}124 the two terms on the second line cancel, while 125 the third line reduces to a single vertical derivative, so it becomes:} 121 126 % 122 & =\frac{1}{e_1 \,e_2 \,e_3 }\left[ {\left. {\;\;\;\frac{\partial }{\partial i}\left( {\frac{e_2 \,e_3 }{e_1 }A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s -e_2 \,\sigma_1 \,A^{lT}\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right. \\127 D^T & =\frac{1}{e_1 \,e_2 \,e_3 }\left[ {\left. {\;\;\;\frac{\partial }{\partial i}\left( {\frac{e_2 \,e_3 }{e_1 }A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s -e_2 \,\sigma_1 \,A^{lT}\;\frac{\partial T}{\partial s}} \right)} \right|_s } \right. \\ 123 128 & \qquad \qquad \quad \shoveright{ \left. {+\frac{\partial }{\partial s}\left( {-e_2 \,\sigma_1 \,A^{lT}\;\left. {\frac{\partial T}{\partial i}} \right|_s +A^{lT}\frac{e_1 \,e_2 }{e_3 }\;\left( {\varepsilon +\sigma_1 ^2} \right)\frac{\partial T}{\partial s}} \right)\;\;\;} \right]} \\ 124 129 % 125 \intertext{ in other words, the horizontal/vertical Laplacian operator in the ($i$,$s$) plane takes the following form:}130 \intertext{In other words, the horizontal/vertical Laplacian operator in the ($i$,$s$) plane takes the following form:} 126 131 \end{array} 127 132 } \\ … … 169 174 \left[ {{ 170 175 \begin{array}{*{20}c} 171 {1+a_ 1 ^2} \hfill & {-a_1 a_2 } \hfill & {-a_1} \hfill \\172 {-a_1 a_2 } \hfill & {1+a_2 ^2} \hfill & {-a_2} \hfill \\173 {-a_1 } \hfill & {-a_2} \hfill & {\varepsilon +a_1 ^2+a_2 ^2} \hfill \\176 {1+a_2 ^2 +\varepsilon a_1 ^2} \hfill & {-a_1 a_2 (1-\varepsilon)} \hfill & {-a_1 (1-\varepsilon) } \hfill \\ 177 {-a_1 a_2 (1-\varepsilon) } \hfill & {1+a_1 ^2 +\varepsilon a_2 ^2} \hfill & {-a_2 (1-\varepsilon)} \hfill \\ 178 {-a_1 (1-\varepsilon)} \hfill & {-a_2 (1-\varepsilon)} \hfill & {\varepsilon +a_1 ^2+a_2 ^2} \hfill \\ 174 179 \end{array} 175 180 }} \right] 176 181 \end{equation} 177 where ($a_1$, $a_2$) are the isopycnal slopes in ($\textbf{i}$, $\textbf{j}$) directions, relative to geopotentials: 182 where ($a_1$, $a_2$) are $(-1) \times$ the isopycnal slopes in 183 ($\textbf{i}$, $\textbf{j}$) directions, relative to geopotentials (or 184 equivalently the slopes of the geopotential surfaces in the isopycnal 185 coordinate framework): 178 186 \[ 179 187 a_1 =\frac{e_3 }{e_1 }\left( {\frac{\partial \rho }{\partial i}} \right)\left( {\frac{\partial \rho }{\partial k}} \right)^{-1} … … 182 190 \right)\left( {\frac{\partial \rho }{\partial k}} \right)^{-1} 183 191 \] 184 185 In practice, isopycnal slopes are generally less than $10^{-2}$ in the ocean, 186 so $\textbf {A}_{\textbf I}$ can be simplified appreciably \citep{cox_OM87}: 192 and, as before, $\epsilon = A^{vT} / A^{lT}$. 193 194 In practice, $\epsilon$ is small and isopycnal slopes are generally less than $10^{-2}$ in the ocean, 195 so $\textbf {A}_{\textbf I}$ can be simplified appreciably \citep{cox_OM87}. Keeping leading order terms\footnote{Apart from the (1,0) 196 and (0,1) elements which are set to zero. See \citet{griffies_bk04}, section 14.1.4.1 for a discussion of this point.}: 187 197 \begin{subequations} 188 198 \label{apdx:B4} … … 226 236 The isopycnal diffusion operator \autoref{apdx:B4}, 227 237 \autoref{apdx:B_ldfiso} conserves tracer quantity and dissipates its square. 228 The demonstration of the first property is trivial as \autoref{apdx:B4} is the divergence of fluxes. 229 Let us demonstrate the second one:238 As \autoref{apdx:B4} is the divergence of a flux, the demonstration of the first property is trivial, providing that the flux normal to the boundary is zero 239 (as it is when $A_h$ is zero at the boundary). Let us demonstrate the second one: 230 240 \[ 231 241 \iiint\limits_D T\;\nabla .\left( {\textbf{A}}_{\textbf{I}} \nabla T \right)\,dv … … 246 256 j}-a_2 \frac{\partial T}{\partial k}} \right)^2} 247 257 +\varepsilon \left(\frac{\partial T}{\partial k}\right) ^2\right] \\ 248 & \geq 0 258 & \geq 0 . 249 259 \end{array} 250 260 } … … 275 285 \end{equation} 276 286 277 where ($r_1$, $r_2$) are the isopycnal slopes in ($\textbf{i}$, $\textbf{j}$) directions, 278 relative to $s$-coordinate surfaces: 287 where ($r_1$, $r_2$) are $(-1)\times$ the isopycnal slopes in ($\textbf{i}$, $\textbf{j}$) directions, 288 relative to $s$-coordinate surfaces (or equivalently the slopes of the 289 $s$-coordinate surfaces in the isopycnal coordinate framework): 279 290 \[ 280 291 r_1 =\frac{e_3 }{e_1 }\left( {\frac{\partial \rho }{\partial i}} \right)\left( {\frac{\partial \rho }{\partial s}} \right)^{-1} … … 284 295 \] 285 296 286 To prove \autoref{apdx:B 5} by direct re-expression of \autoref{apdx:B_ldfiso} is straightforward, but laborious.297 To prove \autoref{apdx:B_ldfiso_s} by direct re-expression of \autoref{apdx:B_ldfiso} is straightforward, but laborious. 287 298 An easier way is first to note (by reversing the derivation of \autoref{sec:B_2} from \autoref{sec:B_1} ) that 288 299 the weak-slope operator may be \emph{exactly} reexpressed in non-orthogonal $i,j,\rho$-coordinates as … … 306 317 the (rotated,orthogonal) isoneutral axes to the non-orthogonal $i,j,\rho$-coordinates. 307 318 The further transformation into $i,j,s$-coordinates is exact, whatever the steepness of the $s$-surfaces, 308 in the same way as the transformation of horizontal/vertical Laplacian diffusion in $z$-coordinates ,319 in the same way as the transformation of horizontal/vertical Laplacian diffusion in $z$-coordinates in 309 320 \autoref{sec:B_1} onto $s$-coordinates is exact, however steep the $s$-surfaces. 310 321 … … 316 327 \label{sec:B_3} 317 328 318 The second order momentum diffusion operator (Laplacian) in the $z$-coordinateis found by329 The second order momentum diffusion operator (Laplacian) in $z$-coordinates is found by 319 330 applying \autoref{eq:PE_lap_vector}, the expression for the Laplacian of a vector, 320 331 to the horizontal velocity vector: … … 361 372 \end{align*} 362 373 Using \autoref{eq:PE_div}, the definition of the horizontal divergence, 363 the third compon ant of the second vector is obviously zero and thus :374 the third component of the second vector is obviously zero and thus : 364 375 \[ 365 \Delta {\textbf{U}}_h = \nabla _h \left( \chi \right) - \nabla _h \times \left( \zeta \ right) + \frac {1}{e_3 } \frac {\partial }{\partial k} \left( {\frac {1}{e_3 } \frac{\partial {\textbf{ U}}_h }{\partial k}} \right)376 \Delta {\textbf{U}}_h = \nabla _h \left( \chi \right) - \nabla _h \times \left( \zeta \textbf{k} \right) + \frac {1}{e_3 } \frac {\partial }{\partial k} \left( {\frac {1}{e_3 } \frac{\partial {\textbf{ U}}_h }{\partial k}} \right) . 366 377 \] 367 378 … … 379 390 - \nabla _h \times \left( {A^{lm}\;\zeta \;{\textbf{k}}} \right) 380 391 + \frac{1}{e_3 }\frac{\partial }{\partial k}\left( {\frac{A^{vm}\;}{e_3 } 381 \frac{\partial {\mathrm {\mathbf U}}_h }{\partial k}} \right) \\392 \frac{\partial {\mathrm {\mathbf U}}_h }{\partial k}} \right) , \\ 382 393 \end{equation} 383 394 that is, in expanded form: … … 386 397 & = \frac{1}{e_1} \frac{\partial \left( {A^{lm}\chi } \right)}{\partial i} 387 398 -\frac{1}{e_2} \frac{\partial \left( {A^{lm}\zeta } \right)}{\partial j} 388 +\frac{1}{e_3} \frac{\partial u}{\partial k}\\399 +\frac{1}{e_3} \frac{\partial }{\partial k} \left( \frac{A^{vm}}{e_3} \frac{\partial u}{\partial k} \right) , \\ 389 400 D^{\textbf{U}}_v 390 401 & = \frac{1}{e_2 }\frac{\partial \left( {A^{lm}\chi } \right)}{\partial j} 391 402 +\frac{1}{e_1 }\frac{\partial \left( {A^{lm}\zeta } \right)}{\partial i} 392 +\frac{1}{e_3} \frac{\partial v}{\partial k}403 +\frac{1}{e_3} \frac{\partial }{\partial k} \left( \frac{A^{vm}}{e_3} \frac{\partial v}{\partial k} \right) . 393 404 \end{align*} 394 405
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