1 | ;+ |
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2 | ; NAME: |
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3 | ; C_TIMECORRELATE |
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4 | ; |
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5 | ; PURPOSE: |
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6 | ; This function computes the "time cross correlation" Pxy(L) or |
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7 | ; the "time cross covariance" between 2 arrays (this is some |
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8 | ; kind of c_correlate but for multidimenstionals arrays) as a |
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9 | ; function of the lag (L). |
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10 | ; |
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11 | ; CATEGORY: |
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12 | ; Statistics. |
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13 | ; |
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14 | ; CALLING SEQUENCE: |
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15 | ; Result = c_timecorrelate(X, Y, Lag) |
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16 | ; |
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17 | ; INPUTS: |
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18 | ; X: an Array which last dimension is the time dimension of |
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19 | ; size n, float or double. |
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20 | ; |
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21 | ; Y: an Array which last dimension is the time dimension of |
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22 | ; size n, float or double. |
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23 | ; |
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24 | ; LAG: A scalar or n-element vector, in the interval [-(n-2), (n-2)], |
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25 | ; of type integer that specifies the absolute distance(s) between |
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26 | ; indexed elements of X. |
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27 | ; |
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28 | ; KEYWORD PARAMETERS: |
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29 | ; COVARIANCE: If set to a non-zero value, the sample cross |
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30 | ; covariance is computed. |
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31 | ; |
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32 | ; DOUBLE: If set to a non-zero value, computations are done in |
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33 | ; double precision arithmetic. |
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34 | ; |
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35 | ; EXAMPLE |
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36 | ; Define two n-element sample populations. |
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37 | ; x = [3.73, 3.67, 3.77, 3.83, 4.67, 5.87, 6.70, 6.97, 6.40, 5.57] |
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38 | ; y = [2.31, 2.76, 3.02, 3.13, 3.72, 3.88, 3.97, 4.39, 4.34, 3.95] |
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39 | ; |
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40 | ; Compute the cross correlation of X and Y for LAG = -5, 0, 1, 5, 6, 7 |
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41 | ; lag = [-5, 0, 1, 5, 6, 7] |
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42 | ; result = c_timecorrelate(x, y, lag) |
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43 | ; |
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44 | ; The result should be: |
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45 | ; [-0.428246, 0.914755, 0.674547, -0.405140, -0.403100, -0.339685] |
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46 | ; |
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47 | ; PROCEDURE: |
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48 | ; |
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49 | ; |
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50 | ; FOR L>=0 |
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51 | ; |
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52 | ; n-L-1 |
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53 | ; sigma (X[k]-Xmean)(Y[k+L]-Ymean) |
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54 | ; k=0 |
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55 | ; correlation(X,Y,L)=------------------------------------------------------ |
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56 | ; n-1 n-1 |
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57 | ; sqrt( (sigma (X[k]-Xmean)^2)*(sigma (Y[k]-Ymean)^2)) |
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58 | ; k=0 k=0 |
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59 | ; |
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60 | ; |
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61 | ; |
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62 | ; n-L-1 |
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63 | ; sigma (X[k]-Xmean)(Y[k+L]-Ymean) |
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64 | ; k=0 |
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65 | ; covariance(X,Y,L)=------------------------------------------------------ |
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66 | ; n |
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67 | ; |
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68 | ; FOR L<0 |
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69 | ; |
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70 | ; |
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71 | ; n-L-1 |
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72 | ; sigma (X[k+L]-Xmean)(Y[k]-Ymean) |
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73 | ; k=0 |
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74 | ; correlation(X,Y,L)=------------------------------------------------------ |
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75 | ; n-1 n-1 |
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76 | ; sqrt( (sigma (X[k]-Xmean)^2)*(sigma (Y[k]-Ymean)^2)) |
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77 | ; k=0 k=0 |
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78 | ; |
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79 | ; |
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80 | ; |
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81 | ; n-L-1 |
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82 | ; sigma (X[k+L]-Xmean)(Y[k]-Ymean) |
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83 | ; k=0 |
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84 | ; covariance(X,Y,L)=------------------------------------------------------ |
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85 | ; n |
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86 | ; |
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87 | ; Where Xmean and Ymean are the time means of the sample populations |
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88 | ; x=(x[t=0],x[t=1],...,x[t=n-1]) and y=(y[t=0],y[t=1],...,y[t=n-1]), |
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89 | ; respectively. |
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90 | ; |
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91 | ; |
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92 | ; |
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93 | ; REFERENCE: |
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94 | ; INTRODUCTION TO STATISTICAL TIME SERIES |
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95 | ; Wayne A. Fuller |
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96 | ; ISBN 0-471-28715-6 |
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97 | ; |
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98 | ; MODIFICATION HISTORY: |
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99 | ; - 01/03/2000 Sebastien Masson (smasson@lodyc.jussieu.fr) |
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100 | ; Based on the C_CORRELATE procedure of IDL |
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101 | ; - August 2003 Sebastien Masson |
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102 | ; update according to the update made in C_CORRELATE by |
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103 | ; W. Biagiotti and available in IDL 5.5 |
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104 | ;- |
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105 | |
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106 | FUNCTION TimeCross_Cov, Xd, Yd, M, nT, Ndim, Double = Double, ZERO2NAN = zero2nan |
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107 | ;Sample cross covariance function. |
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108 | |
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109 | compile_opt hidden |
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110 | ; |
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111 | case Ndim OF |
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112 | 1:res = TOTAL(Xd[0:nT - M - 1L] * Yd[M:nT - 1L] $ |
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113 | , Double = Double) |
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114 | 2:res = TOTAL(Xd[*, 0:nT - M - 1L] * Yd[*, M:nT - 1L] $ |
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115 | , Ndim, Double = Double) |
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116 | 3:res = TOTAL(Xd[*, *, 0:nT - M - 1L] * Yd[*, *, M:nT - 1L] $ |
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117 | , Ndim, Double = Double) |
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118 | 4:res = TOTAL(Xd[*, *, *, 0:nT - M - 1L] * Yd[*, *, *, M:nT - 1L] $ |
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119 | , Ndim, Double = Double) |
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120 | ENDCASE |
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121 | if keyword_set(zero2nan) then begin |
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122 | zero = where(res EQ 0) |
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123 | if zero[0] NE -1 then res[zero] = !values.f_nan |
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124 | ENDIF |
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125 | ; |
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126 | RETURN, res |
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127 | |
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128 | END |
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129 | |
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130 | FUNCTION C_Timecorrelate, X, Y, Lag, Covariance = Covariance, Double = Double |
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131 | |
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132 | ;Compute the sample cross correlation or cross covariance of |
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133 | ;(Xt, Xt+l) and (Yt, Yt+l) as a function of the lag (l). |
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134 | |
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135 | ON_ERROR, 2 |
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136 | |
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137 | xsize = SIZE(X) |
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138 | ysize = SIZE(Y) |
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139 | nt = float(xsize[xsize[0]]) |
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140 | NDim = xsize[0] |
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141 | |
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142 | if total(xsize[0:xsize[0]] NE ysize[0:ysize[0]]) NE 0 then $ |
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143 | MESSAGE, "X and Y arrays must have the same size and the same dimensions" |
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144 | |
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145 | ;Check length. |
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146 | if nt lt 2 then $ |
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147 | MESSAGE, "Time dimension of X and Y arrays must contain 2 or more elements." |
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148 | |
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149 | ;If the DOUBLE keyword is not set then the internal precision and |
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150 | ;result are identical to the type of input. |
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151 | if N_ELEMENTS(Double) eq 0 then $ |
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152 | Double = (Xsize[Xsize[0]+1] eq 5 or ysize[ysize[0]+1] eq 5) |
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153 | |
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154 | if n_elements(lag) EQ 0 then lag = 0 |
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155 | nLag = N_ELEMENTS(Lag) |
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156 | |
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157 | ;Deviations |
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158 | if double then one = 1.0d ELSE one = 1.0 |
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159 | Ndim = size(X, /n_dimensions) |
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160 | Xd = TOTAL(X, Ndim, Double = Double) / nT |
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161 | Xd = X - Xd[*]#replicate(one, nT) |
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162 | Yd = TOTAL(Y, Ndim, Double = Double) / nT |
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163 | Yd = Y - Yd[*]#replicate(one, nT) |
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164 | |
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165 | if nLag eq 1 then Lag = [Lag] ;Create a 1-element vector. |
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166 | |
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167 | case NDim of |
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168 | 1:if Double eq 0 then Cross = FLTARR(nLag) else Cross = DBLARR(nLag) |
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169 | 2:if Double eq 0 then Cross = FLTARR(Xsize[1], nLag) else Cross = DBLARR(Xsize[1], nLag) |
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170 | 3:if Double eq 0 then Cross = FLTARR(Xsize[1], Xsize[2], nLag) $ |
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171 | else Cross = DBLARR(Xsize[1], Xsize[2], nLag) |
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172 | 4:if Double eq 0 then Cross = FLTARR(Xsize[1], Xsize[2], Xsize[3], nLag) $ |
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173 | else Cross = DBLARR(Xsize[1], Xsize[2], Xsize[3], nLag) |
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174 | endcase |
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175 | |
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176 | if KEYWORD_SET(Covariance) eq 0 then begin ;Compute Cross Crossation. |
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177 | for k = 0, nLag-1 do begin |
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178 | if Lag[k] ge 0 then BEGIN |
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179 | case NDim of |
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180 | 1: Cross[k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) |
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181 | 2: Cross[*, k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) |
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182 | 3: Cross[*, *, k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) |
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183 | 4: Cross[*, *, *, k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) |
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184 | endcase |
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185 | ENDIF else BEGIN |
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186 | case NDim of |
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187 | 1: Cross[k] = TimeCross_Cov(Yd, Xd, ABS(Lag[k]), nT, Ndim, Double = Double) |
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188 | 2: Cross[*, k] = TimeCross_Cov(Yd, Xd, ABS(Lag[k]), nT, Ndim, Double = Double) |
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189 | 3: Cross[*, *, k] = TimeCross_Cov(Yd, Xd, ABS(Lag[k]), nT, Ndim, Double = Double) |
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190 | 4: Cross[*, *, *, k] = TimeCross_Cov(Yd, Xd, ABS(Lag[k]), nT, Ndim, Double = Double) |
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191 | endcase |
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192 | ENDELSE |
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193 | ENDFOR |
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194 | div = sqrt(TimeCross_Cov(Xd, Xd, 0L, nT, Ndim, Double = Double, /zero2nan) * $ |
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195 | TimeCross_Cov(Yd, Yd, 0L, nT, Ndim, Double = Double, /zero2nan)) |
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196 | Cross = temporary(Cross)/((temporary(div))[*]#replicate(one, nLag)) |
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197 | endif else begin ;Compute Cross Covariance. |
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198 | for k = 0, nLag-1 do begin |
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199 | if Lag[k] ge 0 then BEGIN |
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200 | case NDim of |
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201 | 1: Cross[k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) / nT |
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202 | 2: Cross[*, k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) / nT |
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203 | 3: Cross[*, *, k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) / nT |
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204 | 4: Cross[*, *, *, k] = TimeCross_Cov(Xd, Yd, Lag[k], nT, Ndim, Double = Double) / nT |
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205 | ENDCASE |
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206 | ENDIF else BEGIN |
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207 | case NDim of |
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208 | 1: Cross[k] = TimeCross_Cov(yd, xd, ABS(Lag[k]), nT, Ndim, Double = Double) / nT |
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209 | 2: Cross[*, k] = TimeCross_Cov(yd, xd, ABS(Lag[k]), nT, Ndim, Double = Double) / nT |
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210 | 3: Cross[*, *, k] = TimeCross_Cov(yd, xd, ABS(Lag[k]), nT, Ndim, Double = Double) / nT |
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211 | 4: Cross[*, *, *, k] = TimeCross_Cov(yd, xd, ABS(Lag[k]), nT, Ndim, Double = Double) / nT |
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212 | ENDCASE |
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213 | ENDELSE |
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214 | endfor |
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215 | endelse |
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216 | |
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217 | if Double eq 0 then RETURN, FLOAT(Cross) else RETURN, Cross |
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218 | |
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219 | END |
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220 | |
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