source: trunk/SRC/Interpolation/spl_incr.pro @ 231

Last change on this file since 231 was 231, checked in by pinsard, 17 years ago

improvements/corrections of some *.pro headers

  • Property svn:keywords set to Id
File size: 19.4 KB
Line 
1;+
2;
3; @file_comments
4;
5; Given the arrays X and Y, which tabulate a function (with the X[i]
6; AND Y[i] in ascending order), and given an input value X2, the
7; SPL_INCR function returns an interpolated value for the given values
8; of X2. The interpolation method is based on cubic spline, corrected
9; in a way that interpolated values are also monotonically increasing.
10;
11; @param x1 {in}{required}
12; An n-element (at least 2) input vector that specifies the tabulate points in
13; a strict ascending order.
14;
15; @param y1 {in}{required}
16; f(x) = y. An n-element input vector that specifies the values
17; of the tabulated function F(Xi) corresponding to Xi. As f is
18; supposed to be monotonically increasing, y values must be
19; monotonically increasing. y can have equal consecutive values.
20;
21; @param x2 {in}{required}
22; The input values for which the interpolated values are
23; desired. Its values must be strictly monotonically increasing.
24;
25; @param der2
26;
27; @param x
28;
29; @returns
30;
31;    y2: f(x2) = y2. Double precision array
32;
33; @restrictions
34; It might be possible that y2[i+1]-y2[i] has very small negative
35; values (amplitude smaller than 1.e-6)...
36;
37; @examples
38;
39; IDL> n = 100L
40; IDL> x = (dindgen(n))^2
41; IDL> y = abs(randomn(0, n))
42; IDL> y[n/2:n/2+1] = 0.
43; IDL> y[n-n/3] = 0.
44; IDL> y[n-n/6:n-n/6+5] = 0.
45; IDL> y = total(y, /cumulative, /double)
46; IDL> x2 = dindgen((n-1)^2)
47; IDL> n2 = n_elements(x2)
48; IDL> print, min(y[1:n-1]-y[0:n-2]) LT 0
49; IDL> y2 = spl_incr( x, y, x2)
50; IDL> splot, x, y, xstyle = 1, ystyle = 1, ysurx=.25, petit = [1, 2, 1], /land
51; IDL> oplot, x2, y2, color = 100
52; IDL> c = y2[1:n2-1] - y2[0:n2-2]
53; IDL> print, min(c) LT 0
54; IDL> print, min(c, max = ma), ma
55; IDL> splot,c,xstyle=1,ystyle=1, yrange=[-.01,.05], ysurx=.25, petit = [1, 2, 2], /noerase
56; IDL> oplot,[0, n_elements(c)], [0, 0], linestyle = 1
57;
58; @history
59;  Sebastien Masson (smasson\@lodyc.jussieu.fr): May-Dec 2005
60;
61; @version
62; $Id$
63;
64;-
65;
66FUNCTION pure_concave, x1, x2, y1, y2, der2, x
67; X^n type
68;
69  compile_opt idl2, strictarrsubs
70;
71  xx = (double(x)-double(x1))/(double(x2)-double(x1))
72  f = (double(x2)-double(x1))/(double(y2)-double(y1))
73  n = der2*temporary(f)
74  res = xx^(n)
75;   IF check_math() GT 0 THEN BEGIN
76;       zero = where(abs(res) LT 1.e-10)
77;       IF zero[0] NE -1 THEN res[zero] = 0.0d
78;   END
79  res = temporary(res)*(double(y2)-double(y1))+y1
80;
81;  IF array_equal(sort(res), lindgen(n_elements(res)) ) NE 1 THEN stop
82  RETURN, res
83END
84
85;+
86; @param x1 {in}{required}
87; An n-element (at least 2) input vector that specifies the tabulate points in
88; a strict ascending order.
89;
90; @param y1 {in}{required}
91; f(x) = y. An n-element input vector that specifies the values
92;    of the tabulated function F(Xi) corresponding to Xi. As f is
93;    supposed to be monotonically increasing, y values must be
94;    monotonically increasing. y can have equal consecutive values.
95;
96; @param x2 {in}{required}
97; The input values for which the interpolated values are
98; desired. Its values must be strictly monotonically increasing.
99;
100; @param der2
101; @param x
102;
103;-
104FUNCTION pure_convex, x1, x2, y1, y2, der2, x
105; 1-(1-X)^n type
106;
107  compile_opt idl2, strictarrsubs
108;
109  xx = 1.0d - (double(x)-double(x1))/(double(x2)-double(x1))
110  f = (double(x2)-double(x1))/(double(y2)-double(y1))
111  n = der2*temporary(f)
112  res = xx^(n)
113;   IF check_math() GT 0 THEN BEGIN
114;       zero = where(abs(res) LT 1.e-10)
115;       IF zero[0] NE -1 THEN res[zero] = 0.0d
116;   END
117  res = 1.0d - temporary(res)
118  res = temporary(res)*(y2-y1)+y1
119;
120;  IF array_equal(sort(res), lindgen(n_elements(res)) ) NE 1 THEN stop
121  RETURN, res
122END
123
124;+
125; @param x
126; @param y
127; @param x2
128; @keyword YP0 The first derivative of the interpolating function at the
129;    point X0. If YP0 is omitted, the second derivative at the
130;    boundary is set to zero, resulting in a "natural spline."
131; @keyword YPN_1 The first derivative of the interpolating function at the
132;    point Xn-1. If YPN_1 is omitted, the second derivative at the
133;    boundary is set to zero, resulting in a "natural spline."
134;-
135FUNCTION spl_incr, x, y, x2, YP0 = yp0, YPN_1 = ypn_1
136;
137  compile_opt idl2, strictarrsubs
138;
139;---------------------------------
140; check and initialization ...
141;---------------------------------
142;
143  nx = n_elements(x)
144  ny = n_elements(y)
145  nx2 = n_elements(x2)
146; x must have at least 2 elements
147  IF nx LT 2 THEN stop
148; y must have the same number of elements than x
149  IF nx NE ny THEN stop
150; x be monotonically increasing
151  IF min(x[1:nx-1]-x[0:nx-2]) LE 0 THEN stop
152; x2 be monotonically increasing
153  IF N_ELEMENTS(X2) GE 2 THEN $
154  IF min(x2[1:nx2-1]-x2[0:nx2-2])  LE 0 THEN stop
155; y be monotonically increasing
156  IF min(y[1:ny-1]-y[0:ny-2]) LT 0 THEN stop
157;---------------------------------
158; first check: check if two consecutive values are equal
159;---------------------------------
160  bad = where(y[1:ny-1]-y[0:ny-2] EQ 0, cntbad)
161  IF cntbad NE 0 THEN BEGIN
162; define the results: y2
163      y2 = dblarr(nx2)
164; define xinx2: see help of value_locate
165;  if xinx2[i] eq -1   :                 x[bad[i]] <  x2[0]
166;  if xinx2[i] eq nx2-1:                 x[bad[i]] >= x2[nx2-1]
167;  else                : x2[xinx2[i]] <= x[bad[i]] <  x2[xinx2[i]+1]
168    xinx2 = value_locate(x2, x[bad])
169    xinx2_1 = value_locate(x2, x[bad+1])
170;
171; left side ... if there is x2 values smaller that x[bad[0]].
172; we force ypn_1 = 0.0d
173    IF xinx2[0] NE -1 THEN BEGIN
174      IF bad[0] EQ 0 THEN BEGIN
175        IF xinx2[0] NE 0 THEN stop
176        y2[0] = y[0]
177      ENDIF ELSE BEGIN
178        y2[0:xinx2[0]] $
179          = spl_incr(x[0:bad[0]], y[0:bad[0]], x2[0:xinx2[0]] $
180                     , yp0 = yp0, ypn_1 = 0.0d)
181      ENDELSE
182    ENDIF
183; flat section
184    IF xinx2_1[0] NE -1 THEN $
185      y2[(xinx2[0]+1) < xinx2_1[0] : xinx2_1[0]] = y[bad[0]]
186; middle pieces ... if cntbad gt 1 then we have to cut spl_incr in
187; more than 2 pieces...
188      IF cntbad GT 1 THEN BEGIN
189; we take care of the piece located wetween bad[ib-1]+1 and bad[ib]
190        FOR ib = 1, cntbad-1 DO BEGIN
191; if there is x2 values smaller that x[bad[ib]], then the x2 values
192; located between bad[ib-1]+1 and bad[ib] are (xinx2_1[ib-1]+1:xinx2[ib]
193; and if we don't have two consecutive flat sections
194          IF xinx2[ib] NE -1 AND (bad[ib-1] NE bad[ib]-1) THEN begin
195            y2[(xinx2_1[ib-1]+1) < xinx2[ib]:xinx2[ib]] $
196              = spl_incr(x[bad[ib-1]+1:bad[ib]], y[bad[ib-1]+1:bad[ib]] $
197                         , x2[(xinx2_1[ib-1]+1) < xinx2[ib]:xinx2[ib]] $
198                         , yp0 = 0.0d, ypn_1 = 0.0d)
199          ENDIF
200; flat section
201          IF xinx2_1[ib] NE -1 THEN $
202            y2[(xinx2[ib]+1) < xinx2_1[ib] : xinx2_1[ib]] = y[bad[ib]]
203        ENDFOR
204      ENDIF
205; right side ... if there is x2 values larger that x[bad[cntbad-1]+1].
206; we force yp0 = 0.0d
207      IF xinx2_1[cntbad-1] NE nx2-1 THEN $
208        y2[xinx2_1[cntbad-1]+1:nx2-1] $
209        = spl_incr(x[bad[cntbad-1]+1:nx-1], y[bad[cntbad-1]+1:nx-1] $
210                        , x2[xinx2_1[cntbad-1]+1:nx2-1] $
211                        , yp0 = 0.0d, ypn_1 = ypn_1new)
212
213    RETURN, y2
214
215  ENDIF
216;-----------
217; compute the second derivative of the cubic spline on each x.
218;-----------
219  yscd = spl_init(x, y, yp0 = yp0, ypn_1 = ypn_1, /double)
220;---------------------------------
221; second check: none of the first derivative on x values must be negative.
222;---------------------------------
223;
224; compute the first derivative on x
225;
226  yifrst = spl_fstdrv(x, y, yscd, x)
227;
228; we force the negative first derivative to 0 by calling again
229; spl_incr with the keywords yp0 and ypn_1 to specify the
230; first derivative equal to 0
231;
232  bad = where(yifrst LT 0.0d, cntbad)
233  IF cntbad NE 0 THEN BEGIN
234;
235; we define the new values of the keyword ypn_1:
236; if the first derivative of the last value of x is negative
237; we define the new values of the keyword ypn_1 to 0.0d0
238    IF bad[cntbad-1] EQ nx-1 THEN BEGIN
239      ypn_1new = 0.0d
240; we remove this case from the list
241      IF cntbad GE 2 THEN bad = bad[0:cntbad-2]
242      cntbad = cntbad-1
243; else we take the value of ypn_1 if it was already defined
244    ENDIF ELSE IF n_elements(ypn_1) NE 0 THEN ypn_1new = ypn_1
245;
246; we define the new values of the keyword yp0:
247; if the first derivative of the first value of x is negative
248; we define the new values of the keyword yp0 to 0.0
249    IF bad[0] EQ 0 THEN BEGIN
250      yp0new = 0.0d
251; we remove this case from the list
252      IF cntbad GE 2 THEN bad = bad[1:cntbad-1]
253      cntbad = cntbad-1
254; else we take the value of yp0 if it was already defined
255    ENDIF ELSE IF n_elements(yp0) NE 0 THEN yp0new = yp0
256;
257; if all the negative derivative corresponded to one of the cases above,
258; then we can directly call spl_incr with the new yp0new and ypn_1new
259    IF cntbad LE 0 THEN BEGIN
260      y2 = spl_incr(x, y, x2, yp0 = yp0new, ypn_1 = ypn_1new)
261;
262; else: there is still cases with negative derivative ...
263; we will cut spl_incr in n spl_incr and specify yp0, ypn_1
264; for each of this n spl_incr
265    ENDIF ELSE BEGIN
266; define xinx2: see help of value_locate
267;  if xinx2[i] eq -1   :                 x[bad[i]] <  x2[0]
268;  if xinx2[i] eq nx2-1:                 x[bad[i]] >= x2[nx2-1]
269;  else                : x2[xinx2[i]] <= x[bad[i]] <  x2[xinx2[i]+1]
270      xinx2 = value_locate(x2, x[bad])
271      y2 = dblarr(nx2)
272; left side ... if there is x2 values smaller that x[bad[0]].
273; we force ypn_1 = 0.0d
274      IF xinx2[0] NE -1 THEN $
275        y2[0:xinx2[0]] $
276        = spl_incr(x[0:bad[0]], y[0:bad[0]], x2[0:xinx2[0]] $
277                        , yp0 = yp0new, ypn_1 = 0.0d)
278; middle pieces ... if cntbad gt 1 then we have to cut spl_incr in
279; more than 2 pieces -> we have middle pieces for which
280; we force yp0 = 0.0d and ypn_1 = 0.0d
281      IF cntbad GT 1 THEN BEGIN
282; we take care of the piece located wetween bad[ib-1] and bad[ib]
283        FOR ib = 1, cntbad-1 DO BEGIN
284; if there is x2 values smaller that x[bad[ib]], then the x2 values
285; located between bad[ib-1] and bad[ib] are (xinx2[ib-1]+1:xinx2[ib]
286          IF xinx2[ib] NE -1 THEN begin
287            y2[(xinx2[ib-1]+1) < xinx2[ib]:xinx2[ib]] $
288              = spl_incr(x[bad[ib-1]:bad[ib]], y[bad[ib-1]:bad[ib]] $
289                              , x2[(xinx2[ib-1]+1) < xinx2[ib]:xinx2[ib]] $
290                              , yp0 = 0.0d, ypn_1 = 0.0d)
291          endif
292        ENDFOR
293      ENDIF
294; right side ... if there is x2 values larger that x[bad[cntbad-1]].
295; we force yp0 = 0.0d
296      IF xinx2[cntbad-1] NE nx2-1 THEN $
297        y2[xinx2[cntbad-1]+1:nx2-1] $
298        = spl_incr(x[bad[cntbad-1]:nx-1], y[bad[cntbad-1]:nx-1] $
299                        , x2[xinx2[cntbad-1]+1:nx2-1] $
300                        , yp0 = 0.0d, ypn_1 = ypn_1new)
301    ENDELSE
302; we return the checked and corrected value of yfrst
303;       FOR i = 0, nx-1 DO BEGIN
304;         same = where(abs(x2- x[i]) LT 1.e-10, cnt)
305; ;        IF cnt NE 0 THEN y2[same] = y[i]
306;       ENDFOR
307    RETURN, y2
308  ENDIF
309;
310; we can be in this part of the code only if:
311;  (1) spl_incr is called by itself
312;  (2) none are the first derivative in x are negative (because they have been
313;      checked and corrected by the previous call to spl_incr, see above)
314;---------------------------------
315; third check: we have to make sure that the first derivative cannot
316;               have negative values between on x[0] and x[nx-1]
317;---------------------------------
318;
319; first we compute the first derivative, next we correct the values
320; where we know that the first derivative can be negative.
321;
322  y2 = spl_interp(x, y, yscd, x2, /double)
323;
324; between x[i] and x[i+1], the cubic spline is a cubic function:
325; y  =  a*X^3 +  b*X^2 + c*X + d
326; y' = 3a*X^2 + 2b*X   + c
327; y''= 6a*X   + 2b
328; if we take X = x[i+1]-x[i] then
329;    d = y[i]; c = y'[i]; b = 0.5 * y''[i],
330;    a = 1/6 * (y''[i+1]-y''[i])/(x[i+1]-x[i])
331;
332; y'[i] and y'[i+1] are positive so y' can be negative
333; between x[i] and x[i+1] only if
334;   1) a > 0
335;            ==> y''[i+1] > y''[i]
336;   2) y' reach its minimum value between  x[i] and x[i+1]
337;      -> 0 < - b/(3a) < x[i+1]-x[i]
338;            ==> y''[i+1] > 0 > y''[i]
339;
340; we do a first selection by looking for those points...
341;
342  loc = lindgen(nx-1)
343  maybebad = where(yscd[loc] LE 0.0d AND yscd[loc+1] GE 0.0d, cntbad)
344;
345  IF cntbad NE 0 THEN BEGIN
346
347    mbbloc = loc[maybebad]
348
349    aaa = (yscd[mbbloc+1]-yscd[mbbloc])/(6.0d*(x[mbbloc+1]-x[mbbloc]))
350    bbb = 0.5d * yscd[mbbloc]
351    ccc = yifrst[mbbloc]
352    ddd = y[mbbloc]
353;
354; definitive selection:
355; y' can become negative if and only if (2b)^2 - 4(3a)c > 0
356; y' can become negative if and only if    b^2  - (3a)c > 0
357;
358    delta = bbb*bbb - 3.0d*aaa*ccc
359;
360    bad = where(delta GT 0, cntbad)
361;
362    IF cntbad NE 0 THEN BEGIN
363      delta = delta[bad]
364      aaa = aaa[bad]
365      bbb = bbb[bad]
366      ccc = ccc[bad]
367      ddd = ddd[bad]
368      bad = maybebad[bad]
369; define xinx2_1: see help of value_locate
370;  if xinx2_1[i] eq -1   :                   x[bad[i]] <  x2[0]
371;  if xinx2_1[i] eq nx2-1:                   x[bad[i]] >= x2[nx2-1]
372;  else                  : x2[xinx2_1[i]] <= x[bad[i]] <  x2[xinx2_1[i]+1]
373      xinx2_1 = value_locate(x2, x[bad])
374; define xinx2_2: see help of value_locate
375;  if xinx2_2[i] eq -1   :                   x[bad[i]+1] <  x2[0]
376;  if xinx2_2[i] eq nx2-1:                   x[bad[i]+1] >= x2[nx2-1]
377;  else                  : x2[xinx2_2[i]] <= x[bad[i]+1] <  x2[xinx2_2[i]+1]
378      xinx2_2 = value_locate(x2, x[bad+1])
379; to avoid the particular case when x2 = x[bad[i]]
380; and there is no other x2 point until x[bad[i]+1]
381      xinx2_1 = xinx2_1 < (xinx2_2-1)
382;
383      FOR ib = 0, cntbad-1 DO BEGIN
384;
385; at least one of the x2 points must be located between
386; x[bad[ib]] and x[bad[ib]+1]
387        IF x2[0] LE x[bad[ib]+1] AND x2[nx2-1] GE x[bad[ib]] THEN BEGIN
388;
389          CASE 1 OF
390            yifrst[bad[ib]+1] EQ 0.0d:BEGIN
391; case pur convex: we use the first derivative of 1-(1-x)^n
392; and ajust n to get the good value: yifrst[bad[ib]] in x[bad[ib]]
393              y2[xinx2_1[ib]+1:xinx2_2[ib]] $
394                = pure_convex(x[bad[ib]], x[bad[ib]+1] $
395                              , y[bad[ib]], y[bad[ib]+1]  $
396                              , yifrst[bad[ib]] $
397                              , x2[xinx2_1[ib]+1:xinx2_2[ib]])
398            END
399            yifrst[bad[ib]] EQ 0.0d:BEGIN
400; case pur concave: we use the first derivative of x^n
401; and ajust n to get the good value: yifrst[bad[ib]+1] in x[bad[ib]+1]
402              y2[xinx2_1[ib]+1:xinx2_2[ib]] $
403                = pure_concave(x[bad[ib]], x[bad[ib]+1] $
404                               , y[bad[ib]], y[bad[ib]+1] $
405                               , yifrst[bad[ib]+1] $
406                               , x2[xinx2_1[ib]+1:xinx2_2[ib]])
407            END
408            ELSE:BEGIN
409; in those cases, the first derivative has 2 zero between
410; x[bad[ib]] and x[bad[ib]+1]. We look for the minimum value of the
411; first derivative that correspond to the inflection point of y
412              xinfl = -bbb[ib]/(3.0d*aaa[ib])
413; we compute the y value for xinfl
414              yinfl = aaa[ib]*xinfl*xinfl*xinfl + bbb[ib]*xinfl*xinfl $
415                + ccc[ib]*xinfl + ddd[ib]
416;
417              CASE 1 OF
418; if y[xinfl] smaller than y[bad[ib]] then we conserve y2 until
419; the first zero of y2 and from this point we use x^n and ajust n to
420; get the good value: yifrst[bad[ib]+1] in x[bad[ib]+1]
421                yinfl LT y[bad[ib]]:BEGIN
422; value of the first zero (y'[xzero]=0)
423                  xzero = (-bbb[ib]-sqrt(delta[ib]))/(3.0d*aaa[ib])
424; value of y[xzero]...
425                  yzero = aaa[ib]*xzero*xzero*xzero + bbb[ib]*xzero*xzero $
426                    + ccc[ib]*xzero + ddd[ib]
427; if yzero > y[bad[ib]+1] then we cannot applay the method we want to
428; apply => we use then convex-concave case by changing by hand the
429; value of yinfl and xinfl
430                  IF yzero GT y[bad[ib]+1] THEN BEGIN
431                    yinfl = 0.5d*(y[bad[ib]+1]+y[bad[ib]])
432                    xinfl = 0.5d*(x[bad[ib]+1]-x[bad[ib]])
433                    GOTO, convexconcave
434                  ENDIF
435; define xinx2_3: see help of value_locate
436;  if xinx2_3[ib] eq -1   :                x[bad[ib]]+xzero <  x2[0]
437;  if xinx2_3[ib] eq nx2-1:                x[bad[ib]]+xzero >= x2[nx2-1]
438;  else                   : x2[xinx2_3] <= x[bad[ib]]+xzero <  x2[xinx3_2+1]
439                  xinx2_3 = value_locate(x2, x[bad[ib]]+xzero)
440; to avoid the particular case when x2 = x[bad[ib]]+xzero
441; and there is no other x2 point until x[bad[ib]+1]
442                  xinx2_3 = xinx2_3 < (xinx2_2[ib]-1)
443                  IF xinx2_2[ib] GE xinx2_3+1 THEN BEGIN
444                    y2[xinx2_3+1:xinx2_2[ib]] $
445                      = pure_concave(x[bad[ib]]+xzero, x[bad[ib]+1] $
446                                     , yzero, y[bad[ib]+1] $
447                                     , yifrst[bad[ib]+1] $
448                                     , x2[xinx2_3+1:xinx2_2[ib]])
449                  ENDIF
450                END
451; if y[xinfl] bigger than y[bad[ib]+1] then we conserve y2 from
452; the second zero of y2 and before this point we use 1-(1-x)^n and
453; ajust n to get the good value: yifrst[bad[ib]] in x[bad[ib]]
454                yinfl GT y[bad[ib]+1]:BEGIN
455; value of the second zero (y'[xzero]=0)
456                  xzero = (-bbb[ib]+sqrt(delta[ib]))/(3.0d*aaa[ib])
457; value of y[xzero]...
458                  yzero = aaa[ib]*xzero*xzero*xzero + bbb[ib]*xzero*xzero $
459                    + ccc[ib]*xzero + ddd[ib]
460; if yzero < y[bad[ib]] then we cannot applay the method we want to
461; apply => we use then convex-concave case by changing by hand the
462; value of yinfl and xinfl
463                  IF yzero lt y[bad[ib]] THEN BEGIN
464                    yinfl = 0.5d*(y[bad[ib]+1]+y[bad[ib]])
465                    xinfl = 0.5d*(x[bad[ib]+1]-x[bad[ib]])
466                    GOTO, convexconcave
467                  ENDIF
468; define xinx2_3: see help of value_locate
469;  if xinx2_3[ib] eq -1   :                x[bad[ib]]+xzero <  x2[0]
470;  if xinx2_3[ib] eq nx2-1:                x[bad[ib]]+xzero >= x2[nx2-1]
471;  else                   : x2[xinx2_3] <= x[bad[ib]]+xzero <  x2[xinx3_2+1]
472                  xinx2_3 = value_locate(x2, x[bad[ib]]+xzero)
473                  IF xinx2_3 ge xinx2_1[ib]+1 THEN BEGIN
474                    y2[xinx2_1[ib]+1:xinx2_3] $
475                      = pure_convex(x[bad[ib]], x[bad[ib]]+xzero  $
476                                    , y[bad[ib]], yzero   $
477                                    , yifrst[bad[ib]] $
478                                    , x2[xinx2_1[ib]+1:xinx2_3])
479                  ENDIF
480                END
481                ELSE:BEGIN
482convexconcave:
483; define xinx2_3: see help of value_locate
484;  if xinx2_3[ib] eq -1   :                x[bad[ib]]+xzero <  x2[0]
485;  if xinx2_3[ib] eq nx2-1:                x[bad[ib]]+xzero >= x2[nx2-1]
486;  else                   : x2[xinx2_3] <= x[bad[ib]]+xzero <  x2[xinx3_2+1]
487                  xinx2_3 = value_locate(x2, x[bad[ib]]+xinfl)
488
489                  IF xinx2_3 ge xinx2_1[ib]+1 THEN BEGIN
490                    y2[xinx2_1[ib]+1:xinx2_3] $
491                      = pure_convex(x[bad[ib]], x[bad[ib]]+xinfl  $
492                                    , y[bad[ib]], yinfl  $
493                                    , yifrst[bad[ib]] $
494                                    , x2[xinx2_1[ib]+1:xinx2_3])
495
496                  ENDIF
497                  IF xinx2_2[ib] GE xinx2_3+1 THEN BEGIN
498                    y2[xinx2_3+1:xinx2_2[ib]] $
499                      = pure_concave(x[bad[ib]]+xinfl, x[bad[ib]+1] $
500                                     , yinfl, y[bad[ib]+1] $
501                                     , yifrst[bad[ib]+1] $
502                                     , x2[xinx2_3+1:xinx2_2[ib]])
503                  ENDIF
504                END
505              ENDCASE
506
507            END
508          ENDCASE
509        ENDIF
510      ENDFOR
511
512    ENDIF
513  ENDIF
514;
515  RETURN, y2
516;
517;------------------------------------------------------------------
518;------------------------------------------------------------------
519;
520END
Note: See TracBrowser for help on using the repository browser.