- Timestamp:
- 2015-02-05T18:54:24+01:00 (9 years ago)
- File:
-
- 1 edited
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branches/2015/dev_r5044_CNRS_LIM3CLEAN/NEMOGCM/NEMO/OPA_SRC/BDY/bdyice_lim.F90
r5055 r5064 229 229 ! Snow energy of melting 230 230 e_s(ji,jj,jk,jl) = rswitch * rhosn * ( cpic * ( rtt - t_s(ji,jj,jk,jl) ) + lfus ) 231 ! Change dimensions 232 e_s(ji,jj,jk,jl) = e_s(ji,jj,jk,jl) / unit_fac 233 ! Multiply by volume, so that heat content in 10^9 Joules 234 e_s(ji,jj,jk,jl) = e_s(ji,jj,jk,jl) * area(ji,jj) * v_s(ji,jj,jl) / nlay_s 231 ! Multiply by volume, so that heat content in J/m2 232 e_s(ji,jj,jk,jl) = e_s(ji,jj,jk,jl) * v_s(ji,jj,jl) / nlay_s 235 233 END DO 236 234 DO jk = 1, nlay_i … … 241 239 + lfus * ( 1.0 - (ztmelts-rtt) / MIN((t_i(ji,jj,jk,jl)-rtt),-epsi20) ) & 242 240 - rcp * ( ztmelts - rtt ) ) 243 ! Correct dimensions to avoid big values 244 e_i(ji,jj,jk,jl) = e_i(ji,jj,jk,jl) / unit_fac 245 ! Mutliply by ice volume, and divide by number of layers to get heat content in 10^9 J 246 e_i(ji,jj,jk,jl) = e_i(ji,jj,jk,jl) * area(ji,jj) * a_i(ji,jj,jl) * ht_i(ji,jj,jl) / nlay_i 241 ! Mutliply by ice volume, and divide by number of layers to get heat content in J/m2 242 e_i(ji,jj,jk,jl) = e_i(ji,jj,jk,jl) * a_i(ji,jj,jl) * ht_i(ji,jj,jl) / nlay_i 247 243 END DO 248 244
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