Version 3 (modified by flavoni, 5 years ago) (diff)

TEST for table (do not read)

How to create an equatorial box, with python scripts.

Test case 1: Equatorial box (180°,60°) : with NO stratification / constant wind trades / NO Coriolis
options values
resolution 2.25° (9/4)
longitude lon_T=[1,179]
latitude lat_T=[-31,31] (to have one point at 0° Equator)
vertical levels 31
batymetry 5000m
NO stratification so=35 / thetao=10 (on ada file TS_init_a.nc)
forcing flx utau = -0.1 wind trades
total time steps 150
output frequency every time step
input files utau=-0.1 / vtau=0 / qtot=0 / qsr=0 / emp=0 on ada file flx.nc

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Test case 2: Equatorial box (180°,60°): with NO stratification / constant wind trades / e2=e1=constant (=1)
options values
resolution 2.25° (9/4)
longitude lon_T=​[1,179]
latitude lat_T=[-31,31] (to have one point at 0° Equator)
vertical levels 31
batymetry 5000m
NO stratification so=35 / thetao=10 (on ada file TS_init_a.nc)
forcing flx utau = -0.1 wind trades
total time steps 150
output frequency every time step
input files utau=-0.1 / vtau=0 / qtot=0 / qsr=0 / emp=0 on ada file flx.nc

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Test case 3: Equatorial box (180°,60°): with NO stratification / constant wind trades / e2 variable with latitude
options values
resolution 2.25° (9/4)
longitude lon_T=​[1,179]
latitude lat_T=[-31,31] (to have one point at 0° Equator)
vertical levels 31
batymetry 5000m
NO stratification so=35 / thetao=10 (on ada file TS_init_a.nc)
forcing flx utau = -0.1 wind trades
total time steps 150
output frequency every time step
input files utau=-0.1 / vtau=0 / qtot=0 / qsr=0 / emp=0 on ada file flx.nc

-

Test case 4: Equatorial box (180°,60°): with stratification / constant wind trades / e2 variable with latitude
options values
resolution 2.25° (9/4)
longitude lon_T=​[1,179]
latitude lat_T=[-31,31] (to have one point at 0° Equator)
vertical levels 31
batymetry 5000m
NO stratification so=35 / thetao=10 (on ada file TS_init_a.nc)
forcing flx utau = -0.1 wind trades
total time steps 150
output frequency every time step
input files utau=-0.1 / vtau=0 / qtot=0 / qsr=0 / emp=0 on ada file flx.nc

-

Test case 5: Equatorial box (180°,60°): with stratification / variable wind trades / e2 variable with latitude
options values
resolution 2.25° (9/4)
longitude lon_T=​[1,179]
latitude lat_T=[-31,31] (to have one point at 0° Equator)
vertical levels 31
batymetry 5000m
NO stratification so=35 / thetao=10 (on ada file TS_init_a.nc)
forcing flx utau = -0.1 wind trades
total time steps 150
output frequency every time step
input files utau=-0.1 / vtau=0 / qtot=0 / qsr=0 / emp=0 on ada file flx.nc

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